Last modified: 2012-03-08 19:06:18 UTC

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Bug 15966 - Provide a way to invoke the Parser from within a PHPUnit test
Provide a way to invoke the Parser from within a PHPUnit test
Product: MediaWiki
Classification: Unclassified
Unit tests (Other open bugs)
All All
: Low enhancement (vote)
: ---
Assigned To: Nobody - You can work on this!
Depends on:
  Show dependency treegraph
Reported: 2008-10-13 15:52 UTC by sharon.dagan
Modified: 2012-03-08 19:06 UTC (History)
4 users (show)

See Also:
Web browser: ---
Mobile Platform: ---
Assignee Huggle Beta Tester: ---


Description sharon.dagan 2008-10-13 15:52:02 UTC
For the sake of unit testing of extensions code, please provide an *easy* way to invoke the Parser from within a PHPUnit test. 

For example:

 *  returns a ready-to-use Parser
class ParserMock {
  var $parser;
  function __constructor() {
     $conf   = new Array( ... );
     $parser = new Parser( $conf );
  function setHook( ... ) {
    $parser->setHook( ... );

  function parse( $text ) {
     $title = new Title( 'test' );
     $opt = new ParserOptions( ... );
     returns $parser->parse( $text, $title, $opt );

class MyFooTagTest extends PHPUnit_Framework_TestCase {
  var $parserMock;
  function setUp() {
    $parserMock = new ParserMock;
    $myFooTag   = new MyFooTag
    $parserMock->setHook( 'foo', array( & $myFooTag, 'foo' ) );

  function testFoo() {
    $out = $parserMock->parse( '<foo f="F">Bar</foo>' );
Comment 1 Tim Starling 2008-10-16 04:24:24 UTC
That's basically how it is already, except you can use the actual Parser class instead of "ParserMock". Have you encountered some problem with this approach?
Comment 2 Antoine "hashar" Musso (WMF) 2012-01-30 17:43:14 UTC
resetting to assignee.
Comment 3 Max Semenik 2012-03-08 19:06:18 UTC
It works this way already. Unless there was something specific requested here, it's WORKSFORME.

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