Last modified: 2006-11-30 03:12:16 UTC

Wikimedia Bugzilla is closed!

Wikimedia migrated from Bugzilla to Phabricator. Bug reports are handled in Wikimedia Phabricator.
This static website is read-only and for historical purposes. It is not possible to log in and except for displaying bug reports and their history, links might be broken. See T10081, the corresponding Phabricator task for complete and up-to-date bug report information.
Bug 8081 - ParserFunctions should not be subst'ed, only their output
ParserFunctions should not be subst'ed, only their output
Status: RESOLVED DUPLICATE of bug 2777
Product: MediaWiki extensions
Classification: Unclassified
General/Unknown (Other open bugs)
unspecified
PC Windows XP
: Normal normal (vote)
: ---
Assigned To: Nobody - You can work on this!
:
Depends on:
Blocks:
  Show dependency treegraph
 
Reported: 2006-11-29 20:50 UTC by Jean-Sébastien Girard
Modified: 2006-11-30 03:12 UTC (History)
0 users

See Also:
Web browser: ---
Mobile Platform: ---
Assignee Huggle Beta Tester: ---


Attachments

Description Jean-Sébastien Girard 2006-11-29 20:50:35 UTC
I can't tell whether this is or not a duplicate of bug 7051. It might be related
to now fixed bug 3298 (Subst'ing ignore includeonly/noinclude).

When you subst a template with ParserFunctions, the ParserFunctions syntax ends
up in the article, whereas you would only want the output. This is especially
troublesome with templates like [[:en:Category:Conversion templates]], which
can't be subst'ed.
Comment 1 Rob Church 2006-11-29 22:16:19 UTC
When you substitute a template with text in it, that text ends up in the page.
If you substitute a template containing a template, what happens?

This is a duplicate of that larger behaviour.
Comment 2 Aryeh Gregor (not reading bugmail, please e-mail directly) 2006-11-30 03:12:16 UTC

*** This bug has been marked as a duplicate of 2777 ***

Note You need to log in before you can comment on or make changes to this bug.


Navigation
Links