Last modified: 2008-05-27 18:31:14 UTC

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Bug 14244 - Don't show pagination where not necessary
Don't show pagination where not necessary
Status: RESOLVED INVALID
Product: MediaWiki
Classification: Unclassified
Search (Other open bugs)
1.12.x
All All
: Normal normal (vote)
: ---
Assigned To: Nobody - You can work on this!
http://en.wikipedia.org/w/index.php?t...
:
Depends on:
Blocks:
  Show dependency treegraph
 
Reported: 2008-05-24 00:36 UTC by Dan Jacobson
Modified: 2008-05-27 18:31 UTC (History)
2 users (show)

See Also:
Web browser: ---
Mobile Platform: ---
Assignee Huggle Beta Tester: ---


Attachments

Description Dan Jacobson 2008-05-24 00:36:31 UTC
Gentlemen, on the search results page we see e.g.,

 Showing below results 1 - 14 of 14

Therefore, printing

 View (previous 20) (next 20) (20 | 50 | 100 | 250 | 500)

is not necessary and distracts the user.

Please apply the knowledge of how many results were found when
deciding if to offer previous/next choices, and how many of them to offer.
Comment 1 Roan Kattouw 2008-05-24 08:39:35 UTC
This knowledge *is* applied in the sense that "next 20" is not a link. If there were >20 search results, "next 20" would be a link to the next 20.
Comment 2 Leon Weber 2008-05-24 08:51:55 UTC
We might grey it out, additionally to not making it a link. Maybe that's clearer.
Comment 3 Dan Jacobson 2008-05-27 18:31:14 UTC
Please consider a device independent view of things.
There are many situations when linked or not linked text will look the
same. Therefore go one step further and just don't print the
non-existent choices. linked or not.
E.g., Google only prints page choices 2 3 4 if that is all there is.

If one cuts and pastes, prints, or mails such choice lists, link vs. non linked distinctions are lost, so it would be best not to print them in the first place
if they don't exist.

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